w^2+5w=3300

Solution for w^2+5w=3300 equation:

w^2+5w=3300

We move all terms to the left:

w^2+5w-(3300)=0

a = 1; b = 5; c = -3300;
Δ = b2-4ac
Δ = 52-4·1·(-3300)
Δ = 13225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{13225}=115$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-115}{2*1}=\frac{-120}{2}
=-60
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+115}{2*1}=\frac{110}{2}
=55
$